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HomeAircraftHelicopterMain Discussion › Calculating Output Horse Power At The Disc, 1HP to 1 lb
03-14-2015 06:06 PM  3 years agoPost 41
AirWolfRC

rrProfessor

42½ N, 83½ W

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Yes, I meant ±16º on the bench . . . 32º total travel.
One question I can think of is . . . is there enough centrifical force at the lower head speed to keep the cone angle down.

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03-14-2015 07:14 PM  3 years agoPost 42
icanfly

rrElite Veteran

ontario

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is there enough centrifical force at the lower head speed to keep the cone angle down.
is this where higher head speed becomes an advantage?

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03-14-2015 07:33 PM  3 years agoPost 43
AirWolfRC

rrProfessor

42½ N, 83½ W

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Beyond some point, it is no longer an advantage. The question is, where is that point.

The cone angle can be calculated. Calculate the effective blade centrifical force at about 75% out from the main shaft and divide the by the heli weight. Take the arc tangent and you have the cone angle.

Two blade rotor disk, 600 lbs centrigugal force per blade, 8 lb heli;
arc-tan(4/600) = 0.38º cone angle (from horizontal)
. . . in a 2G maneuver, that goes to 0.76º

Did you really think the blade grips are what keeps the blades level ?

PS
Here's a teaser, at what speed do your tires stay "inflated" even though they have no air pressure in them ?

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03-14-2015 10:18 PM  3 years agoPost 44
icanfly

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ontario

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excellent, you been a help in ways you'd never expect, thank you for the quality input.
Did you really think the blade grips are what keeps the blades level ?
of course not

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HomeAircraftHelicopterMain Discussion › Calculating Output Horse Power At The Disc, 1HP to 1 lb
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