MPA Elite Veteran Location: Australia
My Posts This: Topic Forum | Hi
I would advise not go under 5K.
Means higher consumption and more heat and serves no purpose.
The 5K value is not a reference to the pot sweep it merely dictates how much current is across the pot resistance bridge from ground to power and reducing the POT ohms just draws more current across it that it doesnt need to signal position.
Remember a POT is equall on both sides of the arm when in the centre.
When it is to one side of the sweep the difference from the other side resistance is the same ratio of difference in a 5K as for a 1K pot.
Example a POT with 180 degree sweep.
0 volt one side and 12 volts the other side.
In the centre at 90 degree a 5k POT is 2.5K each side
A 1K POT is 500R each side
Both cases half the voltage 6V to the servo position feedback input, to it the servo is half way.
At 45 degree to the side a 5K POT may be 1.25K and 3.75K on the other side.
A 1K POT at 45 deg would be say 250R on one side and 750R on the other side.
So in the 5K POT, 45 deg to the 0 side is 1/4 + of the 12v voltage to one side, 3V
OR 45 deg to the 12volt side is 3/4 of 12V, 9V
Same for 1K POT at 45 deg.
3V or 9 V at 45 degreee each side of centre.
Just the 1K POT has more current over the resitance bridge in the POT.
There is no more current going to the servo position feedback input as that draws no current, the chip it only reads the voltage present and compares it to current max voltage to tell where the servo is.
OTH 10K may result in too little over the servo POT resitance bridge and then it may be subject to more interference due to less current over it.
Number of turns is up to you but resistance
Leave it at 5K or the equivelant of the POT that came out of the servo. |